document.write( "Question 725195: z^3=3-3i\r
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document.write( " module argument exponencial representation
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document.write( "solution 1 \r
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document.write( "solution 2\r
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document.write( "solution 3 \n" );
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Algebra.Com's Answer #444008 by stanbon(75887) ![]() You can put this solution on YOUR website! I can't really tell what your problem is. \n" ); document.write( "The z^3 = 3-3i seems to indicate you want to solve for \"z\" \n" ); document.write( "which would be the three cube roots of 3-3i. \n" ); document.write( "If that is true:\r \n" ); document.write( "\n" ); document.write( "z^3=3-3i \n" ); document.write( "module argument exponential representation \n" ); document.write( "---- \n" ); document.write( "r = sqrt(3^2+3^2) = 3sqrt(2) \n" ); document.write( "--- \n" ); document.write( "theta = tan^-1(-3/3) = tan^-1(-1) = (3/4)pi \n" ); document.write( "-------------------- \n" ); document.write( "3 -3i = 3sqrt(2)(cis[(3/4)pi] \n" ); document.write( "z = (3sqrt(2))^(1/3)*(cis(3/4)pi+(2npi)) \n" ); document.write( "Let n = 0 to get z = (3sqrt(2))^(1/3)cis((1/4)pi) \n" ); document.write( "If n = 1 get z = (3sqrt(2))^(1/3)cis((1/4)pi+(2/3)pi) \n" ); document.write( "If n = 2 get z = (3sqrt(2))^(1/3)cis((1/4)pi + (4/3)pi)\r \n" ); document.write( "\n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |