document.write( "Question 725195: z^3=3-3i\r
\n" ); document.write( "\n" ); document.write( " module argument exponencial representation
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\n" ); document.write( "solution 1 \r
\n" ); document.write( "\n" ); document.write( "solution 2\r
\n" ); document.write( "\n" ); document.write( "solution 3
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Algebra.Com's Answer #444008 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I can't really tell what your problem is.
\n" ); document.write( "The z^3 = 3-3i seems to indicate you want to solve for \"z\"
\n" ); document.write( "which would be the three cube roots of 3-3i.
\n" ); document.write( "If that is true:\r
\n" ); document.write( "\n" ); document.write( "z^3=3-3i
\n" ); document.write( "module argument exponential representation
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\n" ); document.write( "r = sqrt(3^2+3^2) = 3sqrt(2)
\n" ); document.write( "---
\n" ); document.write( "theta = tan^-1(-3/3) = tan^-1(-1) = (3/4)pi
\n" ); document.write( "--------------------
\n" ); document.write( "3 -3i = 3sqrt(2)(cis[(3/4)pi]
\n" ); document.write( "z = (3sqrt(2))^(1/3)*(cis(3/4)pi+(2npi))
\n" ); document.write( "Let n = 0 to get z = (3sqrt(2))^(1/3)cis((1/4)pi)
\n" ); document.write( "If n = 1 get z = (3sqrt(2))^(1/3)cis((1/4)pi+(2/3)pi)
\n" ); document.write( "If n = 2 get z = (3sqrt(2))^(1/3)cis((1/4)pi + (4/3)pi)\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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