document.write( "Question 725050: 1. a man cover a distance of 6 km at the rate of 4km/h & cover a distance of 4 km at rate of 3km/h . what is his average speed?\r
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document.write( "2. the average marks obtained by 120 candidate is 35. if average marks of pass candidate is 39 and that of fail candidate is 15 , what is the number of candidate who passed in examination?
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Algebra.Com's Answer #443977 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1. a man cover a distance of 6 km at the rate of 4km/h & cover a distance of 4 km at rate of 3km/h . \n" ); document.write( " what is his average speed? \n" ); document.write( "The total distance traveled: 10km \n" ); document.write( "let a = the average speed for the trip \n" ); document.write( "Write a time equation, time = distance/speed \n" ); document.write( " \n" ); document.write( "multiply equation by 12a to clear the denominators, resulting in: \n" ); document.write( "3a(6) + 4a(4) = 12(10) \n" ); document.write( "18a + 16a = 120 \n" ); document.write( "34a = 120 \n" ); document.write( "a = 120/34 \n" ); document.write( "a ~ 3.53 km/hr is his average speed \n" ); document.write( ": \n" ); document.write( "2. the average marks obtained by 120 candidate is 35. \n" ); document.write( " if average marks of pass candidate is 39 and that of fail candidate is 15, what is the number of candidate who passed in examination? \n" ); document.write( "let p = number that passed \n" ); document.write( "then \n" ); document.write( "(120-p) = number that failed \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply both sides by 120 \n" ); document.write( "39p + 15(120-p) = 120(35) \n" ); document.write( "39p + 1800 - 15p = 4200 \n" ); document.write( "39p - 15p = 4200 - 1800 \n" ); document.write( "24p = 2400 \n" ); document.write( "p = 100 passed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You should check these solutions in the original equations. \n" ); document.write( " |