document.write( "Question 724592: What are the focus and the directrix of the graph of x = 1/24y^2? \r
\n" ); document.write( "\n" ); document.write( "focus (0, –6), directrix x = 6
\n" ); document.write( "focus (6, 0), directrix x = –6
\n" ); document.write( "focus (0, 6), directrix y = –6
\n" ); document.write( "focus (–6, 0), directrix y = 6
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Algebra.Com's Answer #443955 by lwsshak3(11628)\"\" \"About 
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What are the focus and the directrix of the graph of x = 1/24y^2?
\n" ); document.write( "y^2/24=x
\n" ); document.write( "y^2=24x
\n" ); document.write( "This is an equation of a parabola that opens rightward:
\n" ); document.write( "Its basic equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex
\n" ); document.write( "For given equation:
\n" ); document.write( "vertex:(0,0)
\n" ); document.write( "axis of symmetry: x-axis
\n" ); document.write( "4p=24
\n" ); document.write( "p=6
\n" ); document.write( "focus: (6,0) (p-distance to the right of the vertex on the axis of symmetry)
\n" ); document.write( "directrix: x=-6 (p-distance to the left of the vertex on the axis of symmetry)
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