document.write( "Question 63665: if a plane is travelling 3100 km at 790km/h and then encounters a tailwind that boosts its speed tp 990km/h for the next 2800km. what was the total time for the trip?what was teh average speed of the plane for this trip? \n" ); document.write( "

Algebra.Com's Answer #44394 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
The plane travels 3100 km (d1) at 790 km/h (r1) and 2800 km (d2) at 990km/hr (r2)\r
\n" ); document.write( "\n" ); document.write( "Let t1=time it takes the plane to travel 3100km @790km/hr
\n" ); document.write( "and t2=time it takes the plane to travel 2800km @990km/hr \r
\n" ); document.write( "\n" ); document.write( "We'll use the formula:\r
\n" ); document.write( "\n" ); document.write( "distance=(rate)(time) or d=rt\r
\n" ); document.write( "\n" ); document.write( "t1=d1/r1 =(3100 km)/(790km/hr)=3.92 hrs and
\n" ); document.write( "t2=d2/r2 =(2800 km)/(990km/hr)=2.83 hrs\r
\n" ); document.write( "\n" ); document.write( "Total time for the trip =t1+t2=2.83 hrs+3.92 hrs =6.75 hrs\r
\n" ); document.write( "\n" ); document.write( "average rate = (total distance)/(total time)\r
\n" ); document.write( "\n" ); document.write( "total distance =5900 km
\n" ); document.write( "total time=6.75 hrs
\n" ); document.write( "
\n" ); document.write( "average rate=5900/6.75=874.1 km/hr\r
\n" ); document.write( "\n" ); document.write( "ck
\n" ); document.write( "d=rt
\n" ); document.write( "5900 km=(874.1km/hr)(6.75 hr)
\n" ); document.write( "5900 km =5900 km\r
\n" ); document.write( "\n" ); document.write( "Hope this helps. Happy holidays---ptaylor\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );