document.write( "Question 725039: Assume that a savings account earns interest at the rate of 2% compounded monthly . If this account contains $1000 now, how many months will it take for this amount to double if no withdrawals are made? \n" ); document.write( "
Algebra.Com's Answer #443934 by josgarithmetic(39616)\"\" \"About 
You can put this solution on YOUR website!
The interest rates are usually given for year-periods. The 2% interest rate for the year is 2/12 % per month, or 0.1667% per month or 0.001667 as decimal fraction (given to four significant figures, since 1/6 is a repeating decimal).\r
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\n" ); document.write( "\n" ); document.write( "The compounding is monthly, as given in your description.\r
\n" ); document.write( "\n" ); document.write( "Balance is \"highlight%281000%2A%281.001667%29%5Et%29\", where \"t\" is count of months. \r
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\n" ); document.write( "\n" ); document.write( "When will the original deposited principle double? How many months?
\n" ); document.write( "\"2000=1000%281.001667%29%5Et\"
\n" ); document.write( "\"2=1.001667%5Et\"
\n" ); document.write( "Next, you can choose either base 10 or Natural for taking logarithms of both side. I will use base 10:
\n" ); document.write( "\"log%2810%2C2%29=log%2810%2C1.001667%5Et%29\"
\n" ); document.write( "\"log%2810%2C2%29=t%2Alog%2810%2C1.001667%29\"
\n" ); document.write( "\"t=log%2810%2C2%29%2Flog%2810%2C1.001667%29\"
\n" ); document.write( "\"highlight%28t=416%29\" months, almost 35 years.
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