document.write( "Question 63667: The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 32 in., find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #44392 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=width \n" ); document.write( "Then 2x+10=length \n" ); document.write( "P=2L+2W or \n" ); document.write( "32=2(2x+10)+2x and \n" ); document.write( "32=4x+20+2x collect like terms \n" ); document.write( "6x=12 \n" ); document.write( "x=2 in \n" ); document.write( " ck \n" ); document.write( "2(2in)+2(14in)=32in \n" ); document.write( "4+28=32 \n" ); document.write( "32=32\r \n" ); document.write( "\n" ); document.write( "Hope this helps. Happy holidays----ptaylor \n" ); document.write( " |