document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63615>Question 63615</A>: <I><SPAN STYLE=\"word-break: break-all;\"> graphing equations with two variables.   y= -1/2x +3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44389 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> WHAT YOU HAVE IS A STANDARD LINE FORMULA Y=mX+b WHERE m=THE SLOPE (-1/2) & b=THE Y INTERCEPT (0,3).<BR>\n" );
document.write( "THE SLOPE IS FOUND BY THE FOLLOWING FRACTION (Y2-Y1)/X2-X1).<BR>\n" );
document.write( "TO FIND A SECOND POINT USING THIS EAUATION WE SET Y=0 & SOLVE FOR X THUS<BR>\n" );
document.write( "0=-1/2X+3<BR>\n" );
document.write( "1/2X=3<BR>\n" );
document.write( "X=3*2<BR>\n" );
document.write( "X=6 OR (6,0)<BR>\n" );
document.write( "NOW PLOTING THESE TWO POINTS (0,3) &(6,0) & DRAWING A LINE THROUGH THEM YOU HAVE A SLOPE OF -1/2.<BR>\n" );
document.write( "HAPPY GRAFTING  :) \r<BR>\n" );
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