document.write( "Question 724717: solve the equation on the interval 0 < or equal to theta < 2 pi . cot 2theta/3 = -root 3 \n" ); document.write( "

Algebra.Com's Answer #443887 by lwsshak3(11628) $\"\"$ $\"About$

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solve the equation on the interval 0 < or equal to theta < 2 pi . cot 2theta/3 = -root 3
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\n" ); document.write( "cot2x/3=-√3
\n" ); document.write( "cot2x=-3√3=-√3/9
\n" ); document.write( "tan2x=-1/(3√3)=-√3/9
\n" ); document.write( "using inverse tan key of calculator set to radians:
\n" ); document.write( "2x≈π-0.1925, 2π-0.1925=2.9491,6.0907 in quadrants II and IV where tan<0
\n" ); document.write( "x≈1.4746, 3.0454 \n" ); document.write( "

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