document.write( "Question 724719: solve the equation on the interval 0 < or equal to theta < 2pi.
\n" ); document.write( " tan^2 theta = 3/2 sec theta
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Algebra.Com's Answer #443874 by lwsshak3(11628)\"\" \"About 
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solve the equation on the interval 0 < or equal to theta < 2pi.
\n" ); document.write( "tan^2 theta = 3/2 sec theta
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\n" ); document.write( "tan(π/3)^2=(√3)^2=3
\n" ); document.write( "3/2 sec(π/3)=3/2cos(π/3)=3/2*1/2=3
\n" ); document.write( "solution: theta=π/3, 2π/3 (in quadrants I and II where cos and tan have the same sign)
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