document.write( "Question 724724: Jim traveled 240 miles east averaging a speed of 60 miles per hour but at one time he slowed down to 20 miles per hours. If the total time traveled was 8 hours, how many miles were traveled at reduced speeds? \n" ); document.write( "

Algebra.Com's Answer #443871 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+t+\"$ = time in hrs spent going 60 mi/hr
\n" ); document.write( "Let $\"+8+-+t+\"$ = time in hrs spent going 20 mi/hr
\n" ); document.write( "Let $\"+d+\"$ = distance traveled at 60 mi/hr
\n" ); document.write( "----------------
\n" ); document.write( "(1) $\"+d+=+60t+\"$
\n" ); document.write( "(2) $\"+240+-+d+=+20%2A%28+8+-+t+%29+\"$
\n" ); document.write( "-------------------------
\n" ); document.write( "(2) $\"+240+-+d+=+160+-+20t+\"$
\n" ); document.write( "Multiply both sides by $\"+-1+\"$
\n" ); document.write( "(2) $\"+d+-+240+=+20t+-+160+\"$
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+60t+-+240+=+20t+-+160+\"$
\n" ); document.write( "(2) $\"+40t+=+80+\"$
\n" ); document.write( "(2) $\"+t+=+2+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+d+=+60%2A2+\"$
\n" ); document.write( " $\"+d+=+120+\"$
\n" ); document.write( " $\"+240+-+120+=+120+\"$
\n" ); document.write( "120 mi was traveled at an average of 20 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+240+-+d+=+20%2A%28+8+-+t+%29+\"$
\n" ); document.write( "(2) $\"+240+-+120+=+20%2A%28+8+-+2+%29+\"$
\n" ); document.write( "(2) $\"+120+=+20%2A6+\"$
\n" ); document.write( "(2) $\"+120+=+120+\"$
\n" ); document.write( "OK\r
\n" ); document.write( "
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