document.write( "Question 63655: Can you please help me solve using the substitution method?\r
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document.write( "x + y = 1
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document.write( "x + y = 2 \n" );
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Algebra.Com's Answer #44387 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! X+Y=1 \n" ); document.write( "X=1-Y \n" ); document.write( "(1-Y)+Y=2 \n" ); document.write( "1-Y+Y=2 \n" ); document.write( "0Y=1 NO SOLUTION \n" ); document.write( "------------------------------------------ \n" ); document.write( "X+Y=1 & X+Y=2 CANNOT BOTH BE VALID BECAUSE 1 DOES NOT EQUAL 2 \n" ); document.write( "PROOF \n" ); document.write( "SET (X+Y)=Z \n" ); document.write( "NOW SOLVE \n" ); document.write( "Z=1 & Z=2 \n" ); document.write( "Z CANNOT BE 1 & 2 IN THE SAME SET OF LINEAR EQUATIONS. \n" ); document.write( " |