document.write( "Question 63655: Can you please help me solve using the substitution method?\r
\n" ); document.write( "\n" ); document.write( "x + y = 1
\n" ); document.write( "x + y = 2
\n" ); document.write( "

Algebra.Com's Answer #44387 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
X+Y=1
\n" ); document.write( "X=1-Y
\n" ); document.write( "(1-Y)+Y=2
\n" ); document.write( "1-Y+Y=2
\n" ); document.write( "0Y=1 NO SOLUTION
\n" ); document.write( "------------------------------------------
\n" ); document.write( "X+Y=1 & X+Y=2 CANNOT BOTH BE VALID BECAUSE 1 DOES NOT EQUAL 2
\n" ); document.write( "PROOF
\n" ); document.write( "SET (X+Y)=Z
\n" ); document.write( "NOW SOLVE
\n" ); document.write( "Z=1 & Z=2
\n" ); document.write( "Z CANNOT BE 1 & 2 IN THE SAME SET OF LINEAR EQUATIONS.
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