document.write( "Question 63631This question is from textbook An Incremental Development
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document.write( ": please help me to solve the following\r
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document.write( "Use substitution to solve\r
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document.write( "4x + y = 17 and 3x - 5y = 30 \n" );
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Algebra.Com's Answer #44379 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Use substitution to solve\r \n" ); document.write( "\n" ); document.write( "E1: 4x + y = 17 \n" ); document.write( "E2: 3x - 5y = 30 \n" ); document.write( "Solve E1 for y and substitute it into E2 for y and solve for x. \n" ); document.write( "E1: -4x+4x+y=-4x+17 --> y=-4x+17 \n" ); document.write( "E2: 3x-5(-4x+17)=30 \n" ); document.write( "3x+20x-85=30 \n" ); document.write( "23x-85=30 \n" ); document.write( "23x-85+85=30+85 \n" ); document.write( "23x=115 \n" ); document.write( "23x/23=115/23 \n" ); document.write( "x=5 \n" ); document.write( "Substitute x=5 into E1 and solve for y: \n" ); document.write( "E1: 4(5)+y=17 \n" ); document.write( "20+y=17 \n" ); document.write( "-20+20+y=-20+17 \n" ); document.write( "y=-3 \n" ); document.write( "The solution: (x,y)=(5,-3) \n" ); document.write( "Check the solution by substituting 5 in for x and -3 in for y in both equations and see if the equations balance. \n" ); document.write( "E1: 4(5)+(-3)=17 \n" ); document.write( "20-3=17 \n" ); document.write( "17=17 E1 checks. \n" ); document.write( "E2: 3(5)-5(-3)=30 \n" ); document.write( "15+15=30 \n" ); document.write( "30=30 E2 also checks, so we know we're right! \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |