document.write( "Question 724451: An object's height, in meters, when thrown vertically from the ground at a velocity of 80m/s is given by the equation H=-4.9t^2+80t. Ignoring wind resistance, how many seconds will it take the object to return to the ground? in other words, when is H=0? \r
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document.write( "In this problem, I set the equation equal to 0 then I used the quadratic formula but that was wrong....HELP PLEASE!!! \n" );
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Algebra.Com's Answer #443761 by jsmallt9(3758) ![]() You can put this solution on YOUR website! If you use the formula correctly then you can't get the wrong answer. \n" ); document.write( " \n" ); document.write( "a = -4.9 \n" ); document.write( "b = 80 \n" ); document.write( "c = 0 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "which is short for: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The answer of zero reflects the fact that the object started on the ground. The other answer is the one you are looking for. \n" ); document.write( "Of course this problem did not need the quadratic formula. The right side of \n" ); document.write( " \n" ); document.write( "factors! \n" ); document.write( " \n" ); document.write( "From the Zero Product Property: \n" ); document.write( "t = 0 or -4.9t + 80 = 0 \n" ); document.write( "Solving the second one: \n" ); document.write( "t = 0 or t = 800/49 \n" ); document.write( "It's much easier to solve these if you can factor them. The formula is complicated and mistakes can easily be made. (You must have made a mistake yourself if you didn't get the right answer.) \n" ); document.write( " |