document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=724434>Question 724434</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An object's height, in meters, when thrown vertically from the ground at a velocity of 80m/s is given by the equation H=-4.9t^2+80t. Ignoring wind resistance, what is the height of the ball after 2 seconds? 3 seconds? 10 seconds? <BR>\n" );
document.write( "In this problem I substituted the seconds in the given equation, but I was told that was incorrect....HELP PLEASE!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #443738 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=443738\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An object's height, in meters, when thrown vertically from the ground at a velocity of 80m/s is given by the equation H=-4.9t^2+80t. Ignoring wind resistance, what is the height of the ball after 2 seconds? 3 seconds? 10 seconds? <BR>\n" );
document.write( "In this problem I substituted the seconds in the given equation, but I was told that was incorrect....HELP PLEASE!!!<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "2 seconds<BR>\n" );
document.write( "H(2) = -4.9(2^2) + 80(2) = 140.4 meters<BR>\n" );
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document.write( "Do the same for 3 seconds and for 10 seconds.<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );