document.write( "Question 724399: Two people are 3 1/2 miles apart walking towards each other. Their uniform walking differ by 1 mph. They will meet in 1/2 hour. What is the uniform rate of the slower walker? how much of the distance will he/she travel? \n" ); document.write( "
Algebra.Com's Answer #443728 by stanbon(75887) ![]() You can put this solution on YOUR website! Two people are 3 1/2 miles apart walking towards each other. Their uniform walking differ by 1 mph. They will meet in 1/2 hour. What is the uniform rate of the slower walker? how much of the distance will he/she travel? \n" ); document.write( "---- \n" ); document.write( "Faster walker DATA: \n" ); document.write( "rate = r mph ; time = 1/2 hour ; distance = (1/2)r miles \n" ); document.write( "----- \n" ); document.write( "Slower walker DATA: \n" ); document.write( "rate = r-1 mph ; time = 1/2 hour ; distance = (1/2)(r-1) miles \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "(1/2)r + (1/2)(r-1) = 7/2 \n" ); document.write( "--- \n" ); document.write( "r + r -1 = 7 \n" ); document.write( "2r = 8 \n" ); document.write( "r = 4 mph \n" ); document.write( "r-1 = 3 mph (rate of the slower walker. \n" ); document.write( "distance for slower walker: (1/2)3 = 3/2 miles \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================================== \n" ); document.write( " |