document.write( "Question 724219: Take the graph of y=2^x and transform it into y= -3(2)^(2x-4). Label 3 key points on both graphs.\r
\n" ); document.write( "\n" ); document.write( "I've tried graphing it and applying the required stretches and transformations (vertical stretch by 3, horizontal stretch by 1/2, reflection on x-axis, horizontal translation 4 units left) but my graph doesn't match the graph I plug into the calculator. Am I doing something wrong?
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Algebra.Com's Answer #443691 by KMST(5328)\"\" \"About 
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Assuming you meant y equals x squared (y=x^2):
\n" ); document.write( "To transform \"y=x%5E2\" into \"y=-3%282x-4%29%5E2\"
\n" ); document.write( "you need a horizontal translation by 2 units right,
\n" ); document.write( "because you replaced \"z=x-2\" by \"x\" and then by \"2z=2%28x-2%29=2x-4\".
\n" ); document.write( "A little algebra to get a simplified formula for the same function could have helped:
\n" ); document.write( "\"y=-3%282x-4%29%5E2\" --> \"y=-3%282%28x-2%29%29%5E2\" --> \"y=-3%282%5E2%28x-2%29%5E2%29\" --> \"y=-3%284%28x-2%29%5E2%29\" --> \"y=-12%28x-2%29%5E2\"
\n" ); document.write( "Then you would need a vertical stretch by 12, reflection on x-axis, and horizontal translation 2 units right.
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\n" ); document.write( "NOTE: If you meant \"y=sqrt%28x%29\" and \"y=-3sqrt%282x-4%29\"
\n" ); document.write( "the same thing applies.
\n" ); document.write( "\"z%28x%29=%28x-2%29\" puts \"z\" 2 units to the left by subtracting 4, but
\n" ); document.write( "in the compound function \"f%28g%28x%29%29\", to get the same y value you need to add 4 to x:
\n" ); document.write( "\"f%28z%2B2%29=f%28x-2%2B2%29=f%28%28x%2B2%29-2%29=f%28x%29=y\"
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