document.write( "Question 724128: A certain amount is invested at 9% and 12,000 more than that amount is invested at 10%. How much is invested at each rate if the total income is 10,130? \n" ); document.write( "
Algebra.Com's Answer #443604 by nerdybill(7384)\"\" \"About 
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A certain amount is invested at 9% and 12,000 more than that amount is invested at 10%. How much is invested at each rate if the total income is 10,130?
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\n" ); document.write( "Let x = amount ($) invested at 9%
\n" ); document.write( "then
\n" ); document.write( "x+12000 = amount ($) invested at 10%
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\n" ); document.write( ".09x + .10(x+12000) = 10130
\n" ); document.write( ".09x + .10x+1200 = 10130
\n" ); document.write( ".19x+1200 = 10130
\n" ); document.write( ".19x = 8930
\n" ); document.write( "x = 8930/.19
\n" ); document.write( "x = $47000 (invested at 9%)
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\n" ); document.write( "Amount invested at 10%:
\n" ); document.write( "x+12000 = 47000+12000 = $59000
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