document.write( "Question 723383: state what kind of asymptotes the function has, find their equations and find the zeros.\r
\n" ); document.write( "\n" ); document.write( "f(x)=(2x^2-3)/(x+4)\r
\n" ); document.write( "\n" ); document.write( "i dont even know where to start for this one \n" ); document.write( "

Algebra.Com's Answer #443589 by lwsshak3(11628) $\"\"$ $\"About$

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state what kind of asymptotes the function has, find their equations and find the zeros.
\n" ); document.write( "f(x)=(2x^2-3)/(x+4)
\n" ); document.write( "Because the degree of the numerator is one degree higher than that of the denominator, the function has a slant or oblique asymptote. To find it, divide numerator by denominator by long division. The quotient, ignoring the remainder, is the line equation of the slant asymptote.
\n" ); document.write( "(2x^2-3)/(x+4)=(x-8)+Remainder=29
\n" ); document.write( "..
\n" ); document.write( "To find vertical asymptotes, set denominator=0, then solve for x-values that make the function undefined.
\n" ); document.write( "x+4=0
\n" ); document.write( "x≠-4
\n" ); document.write( "..
\n" ); document.write( "To find the zeros, set the function=0, which makes the numerator=0
\n" ); document.write( "2x^2-3=0
\n" ); document.write( "2x^2=3
\n" ); document.write( "x^2=3/2
\n" ); document.write( "x=ą√(3/2) \n" ); document.write( "

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