document.write( "Question 63318:  Please solve:
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document.write( "A trapezoid is formed by lines with the following equations:
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document.write( "2x+4y=16,     x=4,      x=0,        y=0
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document.write( "Find the area of the trapezoid. Show all work and explain. \n" );
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| Algebra.Com's Answer #44358 by venugopalramana(3286)     You can put this solution on YOUR website! Please solve: \n" ); document.write( "A trapezoid is formed by lines with the following equations: \n" ); document.write( "AB SAY 2x+4y=16,BC SAY x=4,DA SAY x=0,CD SAY y=0 \n" ); document.write( "Find the area of the trapezoid. Show all work and explain. \n" ); document.write( "SINCE 2 OPPOSITE SIDES SHOULD BE PARALLEL , THEY ARE X=4 AND X=0 IN THE ABOVE. \n" ); document.write( "A IS INTERSECTION OF AB AND DA...HENCE SOLVING AB AND DA \n" ); document.write( "2X+4Y=16 \n" ); document.write( "X=0 \n" ); document.write( "WE GET \n" ); document.write( "4Y=16 \n" ); document.write( "Y=4 \n" ); document.write( "HENCE A IS (0,4) \n" ); document.write( "SIMILARLY BIS INTERSECTION OF BC AND AB \n" ); document.write( "B IS (4,2) \n" ); document.write( "C IS INTERSECTION F BC AND CD \n" ); document.write( "C IS (4,0) \n" ); document.write( "D IS THE INTERSECION F DA AND CD \n" ); document.write( "D IS (0,0) \n" ); document.write( "SO AREA OF TRAPEZIUM = 0.5[SUM OF PARALLEL SIDES][DISTANCE BETWEEN PARALLEL SIDES] \n" ); document.write( "A = 0.5[BC+DA][DIST.BETWEEN BC AND DA] \n" ); document.write( "A=0.5[(4-4)^2+(2-0)^2][4-0] \n" ); document.write( "A=0.5*4*4=8 SQ.UNITS \n" ); document.write( " |