document.write( "Question 724064: 11. Gundeep invests a total of $5000 in two
\n" );
document.write( "funds. One fund pays interest at 4% per year
\n" );
document.write( "and the second fund pays interest at 6% per
\n" );
document.write( "year. At the end of the year, Gundeep has
\n" );
document.write( "earned $270 in interest. How much did
\n" );
document.write( "Gundeep invest in each fund? \n" );
document.write( "
Algebra.Com's Answer #443568 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 4.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 6.00% per annum ------------ Amount invested = y \n" ); document.write( " 5000 \n" ); document.write( "Interest----- 270 \n" ); document.write( " \n" ); document.write( "Part I 4.00% per annum ---x * \n" ); document.write( "Part II 6.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 5000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "4.00% x + 6.00% y= 270 \n" ); document.write( "Multiply by 100 \n" ); document.write( "4 x + 6 y= 27000.00 --------2 \n" ); document.write( "Multiply (1) by -4 \n" ); document.write( "we get \n" ); document.write( "-4 x -4 y= -20000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x 2 y= 7000 \n" ); document.write( "divide by 2 \n" ); document.write( " y = 3500 - x) \n" ); document.write( "Part I 4.00% $ 1500 \n" ); document.write( "Part II 6.00% $ 3500 \n" ); document.write( " 0.8 \n" ); document.write( "CHECK 0.75 \n" ); document.write( "1500 --------- 4.00% ------- 60.00 260 \n" ); document.write( "3500 ------------- 6.00% ------- 210.00 \n" ); document.write( "Total -------------------- 270.00 \n" ); document.write( " \n" ); document.write( " |