document.write( "Question 723992: Please help with an explanation!!!
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document.write( "Roll a pair of dice. Find the probability of getting either a sum of 7 or atleast one 5.
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document.write( "For the sum of 7, I got 1/6.
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document.write( "For the atleast one 5, I got 11/36.
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document.write( "Here is where I get lost, The probability of (sum of 7 AND atleast one 5) = 1/18.
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document.write( "Explain where the 1/18 comes from so I can understand the remaining problems, and how to solve them. Thank you dearly \n" );
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Algebra.Com's Answer #443509 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Roll a pair of dice. \n" ); document.write( "Find the probability of getting either a sum of 7 or atleast one 5. \n" ); document.write( "For the sum of 7, I got 6/36. \n" ); document.write( "For the at least one 5, I got 11/36. \n" ); document.write( "--------------------------------------------- \n" ); document.write( " The probability of (sum of 7 AND atleast one 5) = 1/18. \n" ); document.write( "Explain where the 1/18 comes from so I can understand the remaining problems, and how to solve them. \n" ); document.write( "------- \n" ); document.write( "P(sum of 7 AND at least one 5) = P(sum of 7) + P(at least one 5) \n" ); document.write( "- P(sum of 7 OR at least one 5) \n" ); document.write( "----- \n" ); document.write( "= (6/36) + (11/36) - (15/36) = (2/36) = 1/18 \n" ); document.write( "------- \n" ); document.write( "Note: The 15/36 comes from 6 where 5 is 1st ; 6 where 5 is 2nd ; \n" ); document.write( "6 where the sum is 7 ; and 3 that satisfy 2 conditions and have \n" ); document.write( "been counted twice: 6+6+6-3 = 15 \n" ); document.write( "========================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |