document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63610>Question 63610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me solve this system of equation using the substitution and elimination methods.\r<BR>\n" );
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document.write( "8x + 9 = -5y<BR>\n" );
document.write( "-3x + 3y = -21 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44350 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8x+5y=-9<BR>\n" );
document.write( "-3x+3y=-21 now multiply the first equatuion by 3 & multiply the second one by 8<BR>\n" );
document.write( "24x+15y=-27<BR>\n" );
document.write( "-24x+24y=-168 now add.<BR>\n" );
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document.write( "39y=-195<BR>\n" );
document.write( "x=-195/39<BR>\n" );
document.write( "x=-5 solution<BR>\n" );
document.write( "3x+3*-5=-21<BR>\n" );
document.write( "3x-15=-21<BR>\n" );
document.write( "3x=6<BR>\n" );
document.write( "x=6/3<BR>\n" );
document.write( "x=2 solution<BR>\n" );
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