document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=723937>Question 723937</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a solution of 40% acid and a solution of 70% acid need to be mixed together to create a solution of 50% acid. how many milliliters of 40% acid should be mixed with 80 milliliters of 70% acid to get the desired mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #443476 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=443476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a solution of 40% acid and a solution of 70% acid need to be mixed together to create a solution of 50% acid. how many milliliters of 40% acid should be mixed with 80 milliliters of 70% acid to get the desired mixture?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "0.40x + 0.70*80 = 0.50(x+80)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "40x + 70*80 = 50x + 50*80<BR>\n" );
document.write( "-10x = -20*80<BR>\n" );
document.write( "x = 160 ml (amt. of 40% solution needed)<BR>\n" );
document.write( "===================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );