document.write( "Question 723868: Please help! Thank you in advance! \r
\n" ); document.write( "\n" ); document.write( "Two ships A and B start from the same port at 8am. Ship A heads north 62 degrees 15 minutes east with a speed of 12 km/hr. Ship B takes the course of north 48 degrees 20 minutes west with the speed of 16 km/hr. How far apart are they at 10:45am? What is the bearing of B from A?
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Algebra.Com's Answer #443447 by stanbon(75887)\"\" \"About 
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Two ships A and B start from the same port at 8am. Ship A heads north 62 degrees 15 minutes east with a speed of 12 km/hr. Ship B takes the course of north 48 degrees 20 minutes west with the speed of 16 km/hr. How far apart are they at 10:45am? What is the bearing of B from A?
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\n" ); document.write( "Draw the picture.
\n" ); document.write( "Distance for A = side A = rate*time = 12*2.75 = 30 km
\n" ); document.write( "Distance for B = side B = rate*time = 16*2.75 = 40 km
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\n" ); document.write( "Angle made by the two sides = C = 62.25+48.33 = 110.58 degrees
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\n" ); document.write( "Solve for side \"c\" using the Law of Cosines.
\n" ); document.write( "c^2 = a^2 + b^2-2ab*cos(C)
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\n" ); document.write( "c = sqrt(3343.63) = 57.82 km
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\n" ); document.write( "Bearing of B from A = 110.58 degrees
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H
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