document.write( "Question 723868: Please help! Thank you in advance! \r
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document.write( "Two ships A and B start from the same port at 8am. Ship A heads north 62 degrees 15 minutes east with a speed of 12 km/hr. Ship B takes the course of north 48 degrees 20 minutes west with the speed of 16 km/hr. How far apart are they at 10:45am? What is the bearing of B from A? \n" );
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Algebra.Com's Answer #443447 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Two ships A and B start from the same port at 8am. Ship A heads north 62 degrees 15 minutes east with a speed of 12 km/hr. Ship B takes the course of north 48 degrees 20 minutes west with the speed of 16 km/hr. How far apart are they at 10:45am? What is the bearing of B from A? \n" ); document.write( "---- \n" ); document.write( "Draw the picture. \n" ); document.write( "Distance for A = side A = rate*time = 12*2.75 = 30 km \n" ); document.write( "Distance for B = side B = rate*time = 16*2.75 = 40 km \n" ); document.write( "------ \n" ); document.write( "Angle made by the two sides = C = 62.25+48.33 = 110.58 degrees \n" ); document.write( "------ \n" ); document.write( "Solve for side \"c\" using the Law of Cosines. \n" ); document.write( "c^2 = a^2 + b^2-2ab*cos(C) \n" ); document.write( "----- \n" ); document.write( "c = sqrt(3343.63) = 57.82 km \n" ); document.write( "================================== \n" ); document.write( "Bearing of B from A = 110.58 degrees \n" ); document.write( "---------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H \n" ); document.write( "---- \n" ); document.write( " \n" ); document.write( " |