document.write( "Question 723725: Rewrite each as an equivalent exponential equation.\r
\n" ); document.write( "\n" ); document.write( "1) log(3)5=y
\n" ); document.write( "2 log(a)7=-2\r
\n" ); document.write( "\n" ); document.write( "Solve
\n" ); document.write( "log(2)x=-3
\n" ); document.write( "log(x)9=1/2
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #443437 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Rewrite each as an equivalent exponential equation.
\n" ); document.write( "1) \"log%283%2C5%29+=+y\"
\n" ); document.write( "The base of 3, raised to the power of y, equals 5
\n" ); document.write( "\"3%5Ey+=+5\"
\n" ); document.write( ":
\n" ); document.write( "2 \"log%28a%2C7%29+=-2\"
\n" ); document.write( "\"a%5E-2+=+7\"
\n" ); document.write( ":
\n" ); document.write( "Solve
\n" ); document.write( "\"log%282%2Cx%29+=+-3\"
\n" ); document.write( "\"2%5E-3+=+x\"
\n" ); document.write( "The reciprocal gets rid of the neg exponent
\n" ); document.write( "\"1%2F%282%5E3%29+=+x\"
\n" ); document.write( "\"1%2F8+=+x\"
\n" ); document.write( ":
\n" ); document.write( "\"log%28x%2C9%29+=+1%2F2\"
\n" ); document.write( "\"x%5E%281%2F2%29+=+9+\"
\n" ); document.write( "square both sides
\n" ); document.write( "\"x%5E%28%281%2F2%29%2A2%29+=+9%5E2\"
\n" ); document.write( "\"x%5E1+=+81\"
\n" ); document.write( "or just
\n" ); document.write( "x = 81
\n" ); document.write( "
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