document.write( "Question 723809: Ok, my question is this:\r
\n" ); document.write( "\n" ); document.write( "Train one leaves town A and moves in the direction of town B with an average speed of 60 km/h Three quarters of an hour later, train 2 leaves town A and moves in the same direction of the first train with an average speed of 90 km/h. Find the time in minutes needed for train 2 to catch up with train 1.\r
\n" ); document.write( "\n" ); document.write( "I know it has to do with simultaneous equations, but i don't know what the values are. Thanks for helping. \n" ); document.write( "
Algebra.Com's Answer #443403 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Train I 60 mph
\n" ); document.write( "Train II 90 mph
\n" ); document.write( "Train I 06:00
\n" ); document.write( "Train II 06:45
\n" ); document.write( "Difference in time= 00:45 => .75 hours
\n" ); document.write( "Train I will have covered 45.00 miles Train II starts
\n" ); document.write( "catch up distance= 45.00 miles
\n" ); document.write( "catch up speed = 90 -60
\n" ); document.write( "catch up speed = 30 mph
\n" ); document.write( "Catchup time = catchup distance/catch up speed
\n" ); document.write( "catch up time= 1.5
\n" ); document.write( "catch up time= 1.50 hours = 90 minutes
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