document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=723851>Question 723851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car leaves a certain town at noon travelling at 40 kph. At 1 pm another car leaves the town travelling at 50 kph. In how many hours will the second car overtake the first car?\r<BR>\n" );
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document.write( "--HELP!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #443399 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=443399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Car I speed 40 km/h\r<BR>\n" );
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document.write( "Car II speed 50 km/h\r<BR>\n" );
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document.write( "Since they are in same direction effective catch up speed = 50-40 = 10 kph\r<BR>\n" );
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document.write( "In 1 hour car I would have traveled 40 km\r<BR>\n" );
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document.write( "catch up time = catch up distance / catch up speed\r<BR>\n" );
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document.write( "xatch up time = 40/10= 4 hours\r<BR>\n" );
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