document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=723804>Question 723804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the ratio of two numberds is 3:4. If the difference is 12 find its smaller number<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #443384 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=443384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the numbers x and y<P><BR>\n" );
document.write( "x/y = 3/4 and y-x = 12 so y=x+12<P><BR>\n" );
document.write( "Substitute that y value (x+12) into the proportion and then solve for x.<P><BR>\n" );
document.write( "x/(x+12) = 3/4   ---> 4x = 3(x+12) = 3x + 36<P><BR>\n" );
document.write( "x=36<P><BR>\n" );
document.write( "y-36 = 12 ---> y = 48<P><BR>\n" );
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