document.write( "Question 723734: Q:-
\n" ); document.write( "Before 5 years, A father is 3 time older than his son.
\n" ); document.write( "after 10 year he becomes twice.
\n" ); document.write( "what is the present age of the father and son?.
\n" ); document.write( "

Algebra.Com's Answer #443325 by lwsshak3(11628)\"\" \"About 
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Before 5 years, A father is 3 time older than his son.
\n" ); document.write( "after 10 year he becomes twice.
\n" ); document.write( "what is the present age of the father and son?.
\n" ); document.write( "***
\n" ); document.write( "Before 5 years:
\n" ); document.write( "x=son's age
\n" ); document.write( "3x=father's age
\n" ); document.write( "..
\n" ); document.write( "At present:
\n" ); document.write( "x+5=age of son.
\n" ); document.write( "3x+5=age of father.
\n" ); document.write( "..
\n" ); document.write( "After 10 years:
\n" ); document.write( "x+15=son's age
\n" ); document.write( "3x+15=father's age
\n" ); document.write( "3x+15=2(x+15)
\n" ); document.write( "3x+15=2x+30
\n" ); document.write( "x=15
\n" ); document.write( "..
\n" ); document.write( "x+5=20
\n" ); document.write( "3x+5=50
\n" ); document.write( "..
\n" ); document.write( "present age of son=20
\n" ); document.write( "present age of father=50
\n" ); document.write( "
\n" );