document.write( "Question 723734: Q:-
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document.write( "Before 5 years, A father is 3 time older than his son.
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document.write( "after 10 year he becomes twice.
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document.write( "what is the present age of the father and son?. \n" );
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Algebra.Com's Answer #443325 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Before 5 years, A father is 3 time older than his son. \n" ); document.write( "after 10 year he becomes twice. \n" ); document.write( "what is the present age of the father and son?. \n" ); document.write( "*** \n" ); document.write( "Before 5 years: \n" ); document.write( "x=son's age \n" ); document.write( "3x=father's age \n" ); document.write( ".. \n" ); document.write( "At present: \n" ); document.write( "x+5=age of son. \n" ); document.write( "3x+5=age of father. \n" ); document.write( ".. \n" ); document.write( "After 10 years: \n" ); document.write( "x+15=son's age \n" ); document.write( "3x+15=father's age \n" ); document.write( "3x+15=2(x+15) \n" ); document.write( "3x+15=2x+30 \n" ); document.write( "x=15 \n" ); document.write( ".. \n" ); document.write( "x+5=20 \n" ); document.write( "3x+5=50 \n" ); document.write( ".. \n" ); document.write( "present age of son=20 \n" ); document.write( "present age of father=50 \n" ); document.write( " |