document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63600>Question 63600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I am not sure how to solve this problem, please help, thanks.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F3%29x%5E%28-2%2F3%29%2B%282%2F3%29x%5E%28-5%2F3%29=0 ALIGN=MIDDLE  ALT=\"%281%2F3%29x%5E%28-2%2F3%29%2B%282%2F3%29x%5E%28-5%2F3%29=0\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44332 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/3)x^(-2/3)+(2/3)x^(-5/3)=0<BR>\n" );
document.write( "Multiply thru by 3 to get:<BR>\n" );
document.write( "x^(-2/3)+2x^(-5/3)=0<BR>\n" );
document.write( "Since x^(-5/3)is the smaller of x^(-2/3) and x^(-5/3), factor it out:<BR>\n" );
document.write( "[x^(-5/3)][x+2]=0<BR>\n" );
document.write( "Then x^(-5/3)=0 or (x-2)=0<BR>\n" );
document.write( "Therefore:  x=0 or x=-2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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