document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8060>Question 8060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please! someone could help me.. i'm really out of idea how can i solve out this problem.\r<BR>\n" );
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document.write( "Find the equation of the straight line perpendiculat to the line with equation y= -2/3x + 3/7 which passes through the point (2,4). giving your answer in the form ax+by+c=0\r<BR>\n" );
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document.write( "please.. help me solve this.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4433 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the line defined by y= -2/3x + 3/7 has gradient -2/3.\r<BR>\n" );
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document.write( "Any line perpendicular to this has a gradient to 3/2. So, we know the equation we want is y = (3/2)x + c.\r<BR>\n" );
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document.write( "We now need the specific equation for that line passing through (2,4), so we then get 4 =(3/2)2 + c which gives 4 = 3 + c. In other words c = 1.\r<BR>\n" );
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document.write( "So the equation is y = (3/2)x + 1\r<BR>\n" );
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document.write( "Now, you don't say if a,b and c are integers?\r<BR>\n" );
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document.write( "If not: y - (3/2)x - 1 = 0\r<BR>\n" );
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document.write( "If whole numbers, just multiply all terms by 2:<BR>\n" );
document.write( " --> 2y - 3x - 2 = 0\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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