document.write( "Question 723515: An arrow shot vertically into the air from ground level with a crossbow reaches a maximum height of 324 feet after 4.5 seconds of flight. Let the quadratic function d(t) represent the distance above ground (in feet) t seconds after the arrow is released. (If air resistance is neglected, a quadratic model provides a good approximation for the flight of a projectile.)
\n" ); document.write( "(A) Find d(t)
\n" ); document.write( "(B) At what times (to two decimal places) will the arrow be 250 feet above the ground?
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Algebra.Com's Answer #443242 by ankor@dixie-net.com(22740)\"\" \"About 
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An arrow shot vertically into the air from ground level with a crossbow reaches a maximum height of 324 feet after 4.5 seconds of flight. Let the quadratic function d(t) represent the distance above ground (in feet) t seconds after the arrow is released. (If air resistance is neglected, a quadratic model provides a good approximation for the flight of a projectile.)
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\n" ); document.write( "(A) Find d(t)
\n" ); document.write( "Find the initial velocity (v) of the arrow using the form -16t^2 + vt = d(t)
\n" ); document.write( "t=4.5, d(t)= 324
\n" ); document.write( "-16(4.5^2) + 4.5v = 324
\n" ); document.write( "-16(20.25) + 4.5v = 324
\n" ); document.write( "-324 + 4.5v = 324
\n" ); document.write( "4.5v = 324 + 324
\n" ); document.write( "4.5v = 648
\n" ); document.write( "v = 648/4.5
\n" ); document.write( "v = 144 ft/sec is the initial upward velocity of the arrow
\n" ); document.write( "the equation
\n" ); document.write( "d(t) = -16t^2 + 144t
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\n" ); document.write( "(B) At what times (to two decimal places) will the arrow be 250 feet above the ground?
\n" ); document.write( "-16t^2 + 144t = 250
\n" ); document.write( "-16t^2 + 144t - 250 = 0
\n" ); document.write( "Solve for t using the quadratic formula,
\n" ); document.write( "I got t = 2.35 and 6.65 sec at 250 ft
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\n" ); document.write( "Graphically, green line is 250 ft, blue line is 324 ft
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-5%2C+15%2C+-100%2C+400%2C+-16x%5E2%2B144x%2C+250%2C+324%29+\"
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