document.write( "Question 723517: \r
\n" ); document.write( "\n" ); document.write( "Joe's boat can go down stream 10 miles in the same time it goes up stream 8 miles. The current of the stream is 2 mph. How fast does Joes boat go in still water?
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Algebra.Com's Answer #443234 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
D=RT
\n" ); document.write( "10=(R+2)T
\n" ); document.write( "T=10/(R+2)
\n" ); document.write( "8=(R-2)T
\n" ); document.write( "T=8/(R-2)
\n" ); document.write( "10/(R+2)=8/(R-2) CROSS MULTIPLY.
\n" ); document.write( "8(R+2)=10(R-2)
\n" ); document.write( "8R+16=10R-20
\n" ); document.write( "8R-10R=-20-16
\n" ); document.write( "-2R=-36
\n" ); document.write( "R=-36/-2
\n" ); document.write( "R=18 MPH FOR THE BOAT IN STILL WATER.
\n" ); document.write( "PROOF:
\n" ); document.write( "10=(18+2)T
\n" ); document.write( "10=20T
\n" ); document.write( "T=20/10
\n" ); document.write( "T=2 HOURS.
\n" ); document.write( "8=(18-2)T
\n" ); document.write( "8=16T
\n" ); document.write( "T=16/8
\n" ); document.write( "T=2 HOURS.\r
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