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document.write( "Joe's boat can go down stream 10 miles in the same time it goes up stream 8 miles. The current of the stream is 2 mph. How fast does Joes boat go in still water? \n" );
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Algebra.Com's Answer #443234 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "10=(R+2)T \n" ); document.write( "T=10/(R+2) \n" ); document.write( "8=(R-2)T \n" ); document.write( "T=8/(R-2) \n" ); document.write( "10/(R+2)=8/(R-2) CROSS MULTIPLY. \n" ); document.write( "8(R+2)=10(R-2) \n" ); document.write( "8R+16=10R-20 \n" ); document.write( "8R-10R=-20-16 \n" ); document.write( "-2R=-36 \n" ); document.write( "R=-36/-2 \n" ); document.write( "R=18 MPH FOR THE BOAT IN STILL WATER. \n" ); document.write( "PROOF: \n" ); document.write( "10=(18+2)T \n" ); document.write( "10=20T \n" ); document.write( "T=20/10 \n" ); document.write( "T=2 HOURS. \n" ); document.write( "8=(18-2)T \n" ); document.write( "8=16T \n" ); document.write( "T=16/8 \n" ); document.write( "T=2 HOURS.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |