document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=723511>Question 723511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have $6000 to invest in stock funds. The first stock pays %5 annual interest and the second one pays %9. If after a year I've made $380 in interest, how much did I invest in each account?<BR>\n" );
document.write( "I only need the equations I don't need to solve it </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #443205 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=443205\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y = 6000 is your first equation since the sum of the two amounts invested must be $6,000\r<BR>\n" );
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document.write( "0.05x + 0.09y = 380 is your other equation since you earn 0.05x dollars in interest in the first account and 0.09y dollars in interest in the second, so they total to 0.05x + 0.09y, which is exactly $380 in interest </SPAN>\n" );
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