document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=723432>Question 723432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a passenger train leaves chicago at the same time a freight train leaves new york. the trains are headed towards each other on parallel tracks. they meet in 4 hours. the two cities are 560 miles apart. if the freight train is traveling 20 mph slower than the passenger train, find the speed of each train. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #443168 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=443168\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Passenger train speed be x<BR>\n" );
document.write( "freight train speed = x-20 \r<BR>\n" );
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document.write( "combined speed = 2x-20\r<BR>\n" );
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document.write( "distance = 560 miles<BR>\n" );
document.write( "Time = 4 hours\r<BR>\n" );
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document.write( "D= speed * time\r<BR>\n" );
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document.write( "560=(2x-20)*4\r<BR>\n" );
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document.write( "560=8x-80<BR>\n" );
document.write( "8x=640<BR>\n" );
document.write( "/8<BR>\n" );
document.write( "x=80\r<BR>\n" );
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document.write( "passenger train 80 mph<BR>\n" );
document.write( "freight train 60 mph </SPAN>\n" );
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