document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=723390>Question 723390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to determine the vertex and zeros of the equation y= 1/4(x+2)^2-5  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #443156 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=443156\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how to determine the vertex and zeros of the equation y= 1/4(x+2)^2-5 <BR>\n" );
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document.write( "The vertex in that form is (-2,-5)<BR>\n" );
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document.write( "Zeros ??<BR>\n" );
document.write( "If x = 0, y = 1-5 = -4<BR>\n" );
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document.write( "Solve: <BR>\n" );
document.write( "(1/4)(x+2)^2-5 = 0<BR>\n" );
document.write( "(x+2)^2 = 20<BR>\n" );
document.write( "x+2 = +-2sqrt(5)<BR>\n" );
document.write( "x = -2+2sqrt(5) or x = -2-2sqrt(5)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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