document.write( "Question 723331: A car radiator is filled with 4 gal of a 30% antifreeze solution. How much pure antifreeze must be added to have a 75% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #443131 by stanbon(75887)\"\" \"About 
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A car radiator is filled with 4 gal of a 30% antifreeze solution. How much pure antifreeze must be added to have a 75% antifreeze solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "anti + anti = anti
\n" ); document.write( "0.30*4 + 1.00*x = 0.75(4+x)
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\n" ); document.write( "Multiply thru by 100 to get:
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\n" ); document.write( "30*4 + 100x = 75*4 + 75x
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\n" ); document.write( "25x = 45*4
\n" ); document.write( "x = (9/5)4
\n" ); document.write( "x = 36/5
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\n" ); document.write( "x = 7 1/5 gallons (amt. of pure antifreeze to add)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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