document.write( "Question 723233: \r
\n" ); document.write( "\n" ); document.write( "Separate the number 50 into three parts so that the second number is twice the first number, and the third number is 5 more than the second number.
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Algebra.Com's Answer #443123 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
F+S+T=50
\n" ); document.write( "S=2F
\n" ); document.write( "T=S+5
\n" ); document.write( "F+2F+2F+5=50
\n" ); document.write( "5F=50-5
\n" ); document.write( "5F=45
\n" ); document.write( "F=45/5
\n" ); document.write( "F=9 ANS FOR THE FIRST NUMBER.
\n" ); document.write( "S=2*9=18 ANS. FOR THE SECOND NUMBER.
\n" ); document.write( "T=18+5=23 ANS. FOR THE THIRD NUMBER.
\n" ); document.write( "PROOF:
\n" ); document.write( "9+18+23=50
\n" ); document.write( "50=50
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