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document.write( "Separate the number 50 into three parts so that the second number is twice the first number, and the third number is 5 more than the second number. \n" );
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Algebra.Com's Answer #443123 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! F+S+T=50 \n" ); document.write( "S=2F \n" ); document.write( "T=S+5 \n" ); document.write( "F+2F+2F+5=50 \n" ); document.write( "5F=50-5 \n" ); document.write( "5F=45 \n" ); document.write( "F=45/5 \n" ); document.write( "F=9 ANS FOR THE FIRST NUMBER. \n" ); document.write( "S=2*9=18 ANS. FOR THE SECOND NUMBER. \n" ); document.write( "T=18+5=23 ANS. FOR THE THIRD NUMBER. \n" ); document.write( "PROOF: \n" ); document.write( "9+18+23=50 \n" ); document.write( "50=50 \n" ); document.write( " |