document.write( "Question 723288: a king hires a crew of 30 workers, who can build a castle wall in 60 days. However, 10 days after the wall was started, the king decided that the wall must be finished in a total of 40 days. How many additional workers must be hired if all the workers work with the same constant rate? \n" ); document.write( "
Algebra.Com's Answer #443113 by josmiceli(19441)\"\" \"About 
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Let \"+R+\" = the rate at which a single worker works
\n" ); document.write( "Add their rates of working to get their rate
\n" ); document.write( "working together
\n" ); document.write( "\"+30R+=+1%2F60+\"
\n" ); document.write( "( the \"+1%2F60+\" means 1 wall / 60 days )
\n" ); document.write( "\"+R+=+1%2F1800+\"
\n" ); document.write( "---------------
\n" ); document.write( "The 30 workers work for 10 days.
\n" ); document.write( "Let \"+x+\" = the fraction of the wall they finish
\n" ); document.write( "\"+30R+=+x%2F10+\"
\n" ); document.write( "\"+1%2F60+=+x%2F10+\"
\n" ); document.write( "\"+x+=+1%2F6+\"
\n" ); document.write( "So, 5/6 of the wall must be finished in \"+40+-+10+=+30+\" days
\n" ); document.write( "Let \"+n+\" = the number of additional workers needed to
\n" ); document.write( "finish the wall in 30 more days
\n" ); document.write( "\"+%28+30+%2B+n+%29%2AR+=+%28+5%2F6+%29+%2F+30+\"
\n" ); document.write( "\"+30R+%2B+n%2AR+=+5%2F180+\"
\n" ); document.write( "\"+n%2AR+=+5%2F180+-+1%2F60+\"
\n" ); document.write( "and, since \"+R+=+1%2F1800+\"
\n" ); document.write( "\"+n%2A%28+1%2F1800+%29+=+50+%2F+1800+-+30%2F1800+\"
\n" ); document.write( "Multiply both sides by \"+1800+\"
\n" ); document.write( "\"+n+=+20+\"
\n" ); document.write( "20 workers must be added to finish in 40 days
\n" ); document.write( "check:
\n" ); document.write( "can \"+30+%2B+20+=+50+\" workers do 5/6 of the wall
\n" ); document.write( "in 30 days?
\n" ); document.write( "\"+50R+=+%28+5%2F6+%29+%2F+30+\"
\n" ); document.write( "\"+50%2A180%2AR+=+5+\"
\n" ); document.write( "\"+R+=+5+%2F+9000+\"
\n" ); document.write( "\"+R+=+1%2F1800+\"
\n" ); document.write( "OK\r
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