document.write( "Question 63397: using matrices 2x-y-z=-3
\n" ); document.write( " x-2y+3z=6
\n" ); document.write( " x+y+z=6
\n" ); document.write( "thank you \n" ); document.write( "
Algebra.Com's Answer #44309 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
SEE THE FOLSolve the system of equations using matrices.
\n" ); document.write( "3x - 2y + z = -7
\n" ); document.write( "x + y - 2z = 12
\n" ); document.write( "3x + y - z = 10
\n" ); document.write( "METHOD:
\n" ); document.write( "1.WRITE THE GIVEN EQNS.AS A MATRIX,EACH EQN.IN ONE ROW AND
\n" ); document.write( "EACH COLUMN AN UNKOWN AND LASTLY THE CONSTANT TERM IN THE SAME ORDER
\n" ); document.write( "2.LITERALLY EACH ROW REPRESENTS ONE EQN. WITH MULTIPLICATION BY
\n" ); document.write( "X,Y,Z AS UNDERSTOOD AND OMITTED AND THE LAST CONSTANT HAVING
\n" ); document.write( "AN = SIGN IN FRONT.
\n" ); document.write( "3.HENCE IF WE MAKE IT IDENTITY MATRIX IN THE UNKNOWNS ZONE ,IT
\n" ); document.write( "WOULD MEAN THE CONSTANT TERMS GIVE VALUES OF UNKNOWNS IN THAT ORDER
\n" ); document.write( "4.ACHIEVE IT BY LINEAR TRANSFORMATIONS AS SHOWN BELOW. \r
\n" ); document.write( "\n" ); document.write( "GIVEN MATRIX EACH EQN.IN A ROW,EACH COLUMN FOR..X,Y,Z AND LAST COL. FOR CONSTANT.
\n" ); document.write( "3 -2 1 -7
\n" ); document.write( "1 1 -2 12
\n" ); document.write( "3 1 -1 10
\n" ); document.write( "R1=R1/3
\n" ); document.write( "1 -0.666666667 0.333333333 -2.333333333
\n" ); document.write( "1 1 -2 12
\n" ); document.write( "3 1 -1 10
\n" ); document.write( "R2=R2-R1
\n" ); document.write( "1 -0.666666667 0.333333333 -2.333333333
\n" ); document.write( "0 1.666666667 -2.333333333 14.33333333
\n" ); document.write( "3 1 -1 10
\n" ); document.write( "R3=R3-3*R1
\n" ); document.write( "1 -0.666666667 0.333333333 -2.333333333
\n" ); document.write( "0 1.666666667 -2.333333333 14.33333333
\n" ); document.write( "0 3 -2 17
\n" ); document.write( "R2=R2/(5/3)
\n" ); document.write( "1 -0.666666667 0.333333333 -2.333333333
\n" ); document.write( "0 1 -1.4 8.6
\n" ); document.write( "0 3 -2 17
\n" ); document.write( "R3=R3-3*R2
\n" ); document.write( "1 -0.666666667 0.333333333 -2.333333333
\n" ); document.write( "0 1 -1.4 8.6
\n" ); document.write( "0 0 2.2 -8.8
\n" ); document.write( "R3=R3/2.2
\n" ); document.write( "1 -0.666666667 0.333333333 -2.333333333
\n" ); document.write( "0 1 -1.4 8.6
\n" ); document.write( "0 0 1 -4
\n" ); document.write( "R2=R2+1.4*R3
\n" ); document.write( "1 -0.666666667 0.333333333 -2.333333333
\n" ); document.write( "0 1 0 3
\n" ); document.write( "0 0 1 -4
\n" ); document.write( "R1=R1-R3/3
\n" ); document.write( "1 -0.666666667 0 -1
\n" ); document.write( "0 1 0 3
\n" ); document.write( "0 0 1 -4
\n" ); document.write( "R1=R1+2R2/3
\n" ); document.write( "1 0 0 1
\n" ); document.write( "0 1 0 3
\n" ); document.write( "0 0 1 -4\r
\n" ); document.write( "\n" ); document.write( "HENCE X=1….Y=3…..Z=-4
\n" ); document.write( "LOWING EXAMPLE AND TRY.IF STILL IN DIFFICULTY PLEASE COME BACK
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