document.write( "Question 723260: A helicopter leaves the air station going 180 mph. 30 minutes later an airplane leaves going 330 mph. How many minutes until the airplane catches up with the helicopter?\r
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document.write( "I set it up as 180x=330(x-30). I don't think it is right though. If you could please help solve this and give the steps too I would be very grateful. Thanks :) \n" );
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Algebra.Com's Answer #443085 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A helicopter leaves the air station going 180 mph. 30 minutes later an airplane leaves going 330 mph. How many minutes until the airplane catches up with the helicopter?\r \n" ); document.write( "\n" ); document.write( "I set it up as 180x=330(x-30). \n" ); document.write( "Solve for x, see if it's right. \n" ); document.write( "180x = 330x - 990 \n" ); document.write( "-150x = -990 \n" ); document.write( "x = 99/15 = 6.6 hours \n" ); document.write( "Seems like a long time. \n" ); document.write( "---------------------- \n" ); document.write( "30 mins = 0.5 hours \n" ); document.write( "d = r*t = 180*0.5 --> the helicopter is 90 miles away when the plane starts \n" ); document.write( "--- \n" ); document.write( "The plane \"gains on\" the h/c at 150 mi/hr (330 - 180) \n" ); document.write( "t = d/r = 90/150 \n" ); document.write( "t = 0.6 hours \n" ); document.write( "t = 36 minutes \n" ); document.write( " \n" ); document.write( " |