document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=723099>Question 723099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have another question.  Given that the measure of angle a= 74 degrees and the measure of angle b= 52 degrees, find the measure of angles x and y. In the drawing, angle x is on the lower right interior of the triangle and angle y is on the lower right exterior of the triangle.  I am so totally lost...please help...\r<BR>\n" );
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document.write( "Becky </SPAN>\n" );
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document.write( "I have another question.  Given that the measure of angle a= 74 degrees and the measure of angle b= 52 degrees, find the measure of angles x and y. In the drawing, angle x is on the lower right interior of the triangle and angle y is on the lower right exterior of the triangle.  I am so totally lost...please help...\r<BR>\n" );
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document.write( "Becky\r<BR>\n" );
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document.write( "Based on your description, x seems to be the third angle of the triangle, while y appears to be one of the exterior angles of the triangle, formed by extending one of the triangle's sides.\r<BR>\n" );
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document.write( "As the angles of a triangle sum to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180%5Eo ALIGN=MIDDLE  ALT=\"180%5Eo\"   DISABLED_style= \"max-width:90%; height:auto;\" >, we can say that x = 180 - (a + b), or x = 180 - (74 + 52), or x = 180 - 126, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28x+=+54%5Eo%29 ALIGN=MIDDLE  ALT=\"highlight_green%28x+=+54%5Eo%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "As the angles on a straight line are SUPPLEMENTARY (sum to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180%5Eo ALIGN=MIDDLE  ALT=\"180%5Eo\"   DISABLED_style= \"max-width:90%; height:auto;\" >), and as x and y are on a straight line, we can say that x + y = 180. Now, since x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=54%5Eo ALIGN=MIDDLE  ALT=\"54%5Eo\"   DISABLED_style= \"max-width:90%; height:auto;\" >, then 54 + y = 180 ----- y = 180 - 54, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28y+=+126%5Eo%29 ALIGN=MIDDLE  ALT=\"highlight_green%28y+=+126%5Eo%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "OR\r<BR>\n" );
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document.write( "As any exterior angle, formed by extending one side of a triangle, is the sum of the two opposite interior angles, we can say that: y = a + b, or y = 74 + 52, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28y+=+126%5Eo%29 ALIGN=MIDDLE  ALT=\"highlight_green%28y+=+126%5Eo%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com </SPAN>\n" );
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