document.write( "Question 723055: the length of a rectangle is 4cm less than twice its width.it's perimeter is 40cm.find it's length and width. \n" ); document.write( "

Algebra.Com's Answer #443007 by 119078(26) $\"\"$ $\"About$

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Write down and draw what you know to start.
\n" ); document.write( "Now it may seem tricky but \"4cm less than twice its width\" is very easy. Just brake it up into parts. The ending say 2 its width so 2w, then 4 cm less than which is -4. Put it all together and you have 2w-4=length.
\n" ); document.write( "Length=2w-4
\n" ); document.write( "Width=?
\n" ); document.write( "Perimeter=40cm
\n" ); document.write( "Now you need to plug in the variables into the perimeter formula.
\n" ); document.write( " $\"P=2%28l%29%2B2%28w%29\"$
\n" ); document.write( " $\"40=2%282w-4%29%2B2%28w%29\"$
\n" ); document.write( "Distribute 2 into $\"2w-4\"$
\n" ); document.write( " $\"40=4w-8%2B2w\"$
\n" ); document.write( "Add like terms.
\n" ); document.write( " $\"40=6w-8\"$
\n" ); document.write( "Add 8 to both sides.
\n" ); document.write( " $\"%2840%2B8%29=6w%28-8%2B8%29\"$
\n" ); document.write( " $\"48=6w\"$
\n" ); document.write( "Divide 6 to both sides.
\n" ); document.write( " $\"%2848%2F6%29=%286w%2F6%29\"$
\n" ); document.write( " $\"8=w\"$
\n" ); document.write( "Find length
\n" ); document.write( " $\"l=2%288%29-4\"$
\n" ); document.write( " $\"l=16-4\"$
\n" ); document.write( " $\"l=12\"$
\n" ); document.write( "Answer
\n" ); document.write( " $\"8=w\"$ & $\"l=12\"$
\n" ); document.write( "I hope this step by step helps you out :)! \n" ); document.write( "

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