document.write( "Question 723018: A few families took a trip to an amusement park together. Tickets cost $7.50 each for adults and $3.50 each for kids, and the group paid $65.00 in total. There were 6 fewer adults than kids in the group.\r
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document.write( "Find the number of adults and kids on the trip. \n" );
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Algebra.Com's Answer #442998 by mananth(16946) You can put this solution on YOUR website! x= number of kids \n" ); document.write( "y= number of adults \n" ); document.write( " \n" ); document.write( "1.00 x -1.00 y = 6.00 .............1 \n" ); document.write( "Total value \n" ); document.write( "3.50 x + 7.50 y = 65.00 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by 7.50 \n" ); document.write( "Multiply (2) by 1.00 \n" ); document.write( "7.50 x -7.50 y = 45.00 \n" ); document.write( "3.50 x + 7.50 y = 65.00 \n" ); document.write( "Add the two equations \n" ); document.write( "11.00 x = 110.00 \n" ); document.write( "/ 11.00 \n" ); document.write( "x = 10.00 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1.00 x -1.00 y = 6.00 \n" ); document.write( "10.00 -1.00 y = 6.00 \n" ); document.write( " -1.00 y = 6.00 -10 \n" ); document.write( " -1.00 y = -4.00 \n" ); document.write( " y = 4.00 \n" ); document.write( "x= 10.00 number of kids \n" ); document.write( "y= 4.00 number of adults \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |