document.write( "Question 722871: log5x = log5 (x+4) -2
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Algebra.Com's Answer #442976 by stanbon(75887) $\"\"$ $\"About$

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log5x = log5 (x+4) -2
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\n" ); document.write( "log5(x) - log5(x+4) = -2
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\n" ); document.write( "log5[x/(x+4)] = -2
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\n" ); document.write( "x/(x+4) = 1/25
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\n" ); document.write( "25x = x + 4
\n" ); document.write( "24x = 4
\n" ); document.write( "x = 1/6
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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