document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=722697>Question 722697</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "A part of $6000 was invested at 6% annual interest and the remaining at 7% annual interest. At the end of the year the total received was $6391. How much money was invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #442858 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=442858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(1+R)^T<BR>\n" );
document.write( "X(1+.07)^1+(6000-X)(1+.06)^1=6391<BR>\n" );
document.write( "1.07X+(6000-X)*1.06=6391<BR>\n" );
document.write( "1.07X+6360-1.06X=6391<BR>\n" );
document.write( ".01X=6391-6360<BR>\n" );
document.write( ".01X=31<BR>\n" );
document.write( "X=31/.01<BR>\n" );
document.write( "X=$3,100 INVESTED @ 7%<BR>\n" );
document.write( "6000-3100=$2,900 AMOUNT INVESTED @ 6%.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "3100*1.07+2900*1.06=6391<BR>\n" );
document.write( "3317+3074=6391<BR>\n" );
document.write( "6391=6391 </SPAN>\n" );
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