document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=722565>Question 722565</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The present ages of Lewis and Brown are in the ratio 1:2. <BR>\n" );
document.write( "Three years from now, the ages will be in the ratio 3:5. Find the present ages of Lewis and Brown. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #442790 by </B><A HREF=/tutors/aboutme.mpl?userid=god2012><B>god2012(113)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=god2012><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=god2012><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=442790\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution:\r<BR>\n" );
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document.write( "Let 'x' be the common factor in the ages of Lewis and Brown.\r<BR>\n" );
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document.write( "Age of Lewis is x years<BR>\n" );
document.write( "Age of Brown is 2x years\r<BR>\n" );
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document.write( "After 3 years, their ages will be (x+3) and (2x+3) respectively.\r<BR>\n" );
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document.write( "(x+3)/(2x+3) = 3/5\r<BR>\n" );
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document.write( "5x+15 = 6x+9<BR>\n" );
document.write( "x = 6 years <BR>\n" );
document.write( "2x = 12 years\r<BR>\n" );
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document.write( "Age of Lewis = 6 years<BR>\n" );
document.write( "Age of Brown = 12 years<BR>\n" );
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