document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=722551>Question 722551</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Juan invests a total of $39,000 in two accounts paying 14% and 11% annual interest, respectively. How much was invested in each account if, after one year, the total interest was $4,860.00.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #442783 by </B><A HREF=/tutors/aboutme.mpl?userid=god2012><B>god2012(113)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=god2012><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=god2012><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=442783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Total Principal = $39000<BR>\n" );
document.write( "Total interest paid = $4860\r<BR>\n" );
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document.write( "Simple interest = I = PTR/100\r<BR>\n" );
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document.write( "let 'x' be the amount invested in first account with 14% interest<BR>\n" );
document.write( "and 39000 - x is the amount invested in 2nd account with 11%\r<BR>\n" );
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document.write( "I1 = x * 14/100<BR>\n" );
document.write( "I2 = (39000-x)*11/100\r<BR>\n" );
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document.write( "I1+I2 = (1/100) *(14x + 429000 - 11x ) = (1/100)*(3x + 429000) = 4860\r<BR>\n" );
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document.write( "3x = 486000 - 429000 = 57000 or x = 19000  and 39000-x = 20000\r<BR>\n" );
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document.write( "Therefore, Juan invested $19000 in first and $20000 in the 2nd account respectively </SPAN>\n" );
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