document.write( "Question 722492: find the coordinates of the midpoint of the chord in the line x+2y-1=0 which intersects the ellipse x^2+2y^2=3 \n" ); document.write( "
Algebra.Com's Answer #442779 by lwsshak3(11628)\"\" \"About 
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find the coordinates of the midpoint of the chord in the line x+2y-1=0 which intersects the ellipse x^2+2y^2=3
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\n" ); document.write( "x+2y-1=0
\n" ); document.write( "x^2+2y^2=3
\n" ); document.write( "..
\n" ); document.write( "x=(-2y+1)
\n" ); document.write( "(-2y+1)^2+2y^2=3
\n" ); document.write( "4y^2-4y+1+2y^2-3=0
\n" ); document.write( "6y^2-4y-2=0
\n" ); document.write( "3y^2-2y-1=0
\n" ); document.write( "(3y+1)(y-1)=0
\n" ); document.write( "y=-1/3
\n" ); document.write( "x=2/3+1=5/3
\n" ); document.write( "or
\n" ); document.write( "y=1
\n" ); document.write( "x=-2+1=-1
\n" ); document.write( "points of intersection: (5/3,-1/3) and (-1,1)
\n" ); document.write( "midpoint coordinates of chord: (-1+5/3)/2, (1-1/3)/2=(1/3,1/3)
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