document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=722524>Question 722524</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can't solve the following problem about a three-digit number:The sum of the three digits is 12 . The tens digit exceeds  the hundred digit by the same amount that the units digit exceeds the tens digit. If the digits are reversed, the new number exceeds the original number by 198. Find the original number. For the first equation I got h+t+u=12,but I just can't find the second.Please help!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #442766 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=442766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> h+t+u=12...............(1)\r<BR>\n" );
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document.write( "t-h=u-t<BR>\n" );
document.write( "2t-h-u=0..................(2)\r<BR>\n" );
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document.write( "100u+10t+h-198 = 100h+10t+u\r<BR>\n" );
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document.write( "99u-99h=198\r<BR>\n" );
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document.write( "/99<BR>\n" );
document.write( "u-h=2...................(3)\r<BR>\n" );
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document.write( "solve for h t u\r<BR>\n" );
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document.write( "345 is the number </SPAN>\n" );
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